i have no idea

Question

0

616

1

Find $x = \sqrt{ 3 + \sqrt{ 3 + \sqrt{ 3 + \sqrt{ \ldots } } } }$

Guest Jun 30, 2020

thelizzybeth · Answer 1 · 2020-06-30T11:12:22

This equals $x=\sqrt{3+x}$

Square both sides $x^2=3+x$ .

Then factorize $x^2-x-3=0$ .

Since this expression is clearly positive, x= $\frac{1+\sqrt{13}}{2}$