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a=l+w    l=(8^2*3.14)+(8^2*3.142)  w=c*14     c=3.142*16

 Mar 16, 2020
edited by TacoBell  Mar 16, 2020
edited by TacoBell  Mar 16, 2020
 #1
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Are 3.14 and 3.142 both supposed to be pi?

 Mar 16, 2020
 #2
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Simplify both I and w

\(I=(8^2*3.14)+(8^2*3.142)\) I assume 3.14 is "pi" so

\(I=(8^2*\varpi )+(8^2*\varpi )\) Factor

\(I=(8^2*\varpi )(1+1)=2(8^2*\varpi )\)

Now w

\(w=(\varpi *16*14)\)

\(a=l+w\)

\(a=2(8^2*\varpi )+(\varpi *16*14)\)

\(a=2*8^2*\varpi +\varpi *16*14\)

\(a=2*8*8*\varpi +\varpi *2*8*2*7\)

Factor, 2,8, \(\varpi \)

\(16\varpi (8+2*7)\)

\(16\varpi (22)\)

\(22*16*\varpi \)

\(2(11*16*\varpi )\)

\(11*32*\varpi \)

\(352\varpi \) = \(1091\) (Exactly, 1105.841...) However, a good approximate without a calculator is assuming \(\varpi =3.10\)

.
 Mar 17, 2020
edited by Guest  Mar 17, 2020
edited by Guest  Mar 17, 2020

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