the value of a $3,000 investment at 5% annual interest is found to be A(t)=3000(1.05)^t at t years after the initial investment. find the value after 6 years.
+118667 the value of a $3,000 investment at 5% annual interest is found to be A(t)=3000(1.05)^t at t years after the initial investment. find the value after 6 years.
Just replece the t with a 6 and put it into the calculator
A(t)=3000(1.05)^t
A(6)=3000(1.05)^6
3000*(1.05)^6 ???
