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the value of a $3,000 investment at 5% annual interest is found to be A(t)=3000(1.05)^t at t years after the initial investment. find the value after 6 years.

Guest Mar 29, 2017
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the value of a $3,000 investment at 5% annual interest is found to be A(t)=3000(1.05)^t at t years after the initial investment. find the value after 6 years.

 

Just replece the t with a 6 and put it into the calculator

 

A(t)=3000(1.05)^t

A(6)=3000(1.05)^6

 

3000*(1.05)^6   ??? 

Melody  Mar 29, 2017

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