I know a way by which i can make i can get total of 120 by using five zeros 0,0,0,0,0 and any one mathematical operator. Do you?
(0!+0!+0!+0!+0!)!=(1+1+1+1+1)!=5!=1*2*3*4*5=120
The operator is the factorial (!).
(0!+0!+0!+0!+0!)!=(1+1+1+1+1)!=5!=1*2*3*4*5=120
The operator is the factorial (!).
The plus sign (+) is also a mathematical operator, so you've used two operators. No cookie for you!
He didn't say only one mathematical operator, so it means I can use two ones.
And, if you're so smart Anonymous, find a way you can do it using one mathematical operator.
Good luck !
I found two other ways (the second is a little bit tricky, since a 8 is formed by a 0 put atop another 0)
[(0!+0!)(0!+0!)+0!]!=[(1+1)(1+1)+1]!=(4+1)!=5!=120
$$({\sqrt{({\sqrt{{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}}}}){!}{\mathtt{\,\small\textbf+\,}}{\mathtt{0}}{!}}}){!}$$=$$({\sqrt{({\sqrt{{\mathtt{16}}}}){!}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}}}){!}$$=$$({\sqrt{{\mathtt{4}}{!}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}}}){!}$$=$$({\sqrt{{\mathtt{25}}}}){!}$$=5!=120
"any one mathematical operator" - any one means ONLY one
That is a quote from the question.
It doesn't matter though - I liked your answer :)
I like you second answer too.
I would like to see anon do it with ony one operator as well LOL
You're right Melody, when I posted it I realized how stupid my remark was
I found a fourth way :
[(0! + 0!)(0! + 0!) + 0!]!=(2²+1)!=(4+1)!=5!=120
But it seems to be impossible to do with only one symbol.
It wasn't that stupid - I can understand your annoyance.
You have presented some really clever answers there :)
Morgan Tud’s solutions:
web2.0calc . com /questions/a-question-you-can-answer#r6
Technically his second answer is only two operators because “NOT” is a logical operator.
You still don’t get a cookie!
Then nobody will get a cookie, because it is impossible to do with only one operator.
And I don't give a d**n if I don't get a cookie, since I have got a full pack.
Is that why you give them away?
The one you gave CPhill looked like it had roach droppings on it.
The first answer [cos(0)+cos(0)+cos(0)+cos(0)+cos(0)]! is right since cos(0)=1, but the second one is wrong (not(0)=-1 so [not(0)+not(0)+not(0)+not(0)+not(0)]!=(-1-1-1-1-1)!=(-5)!=MATH ERROR)