I know a way by which i can make i can get total of 120 by using five zeros 0,0,0,0,0 and any one mathematical operator. Do you?

Trincent
May 19, 2015

#1**+16 **

(0!+0!+0!+0!+0!)!=(1+1+1+1+1)!=5!=1*2*3*4*5=120

The operator is the factorial (!).

EinsteinJr
May 19, 2015

#1**+16 **

Best Answer

(0!+0!+0!+0!+0!)!=(1+1+1+1+1)!=5!=1*2*3*4*5=120

The operator is the factorial (!).

EinsteinJr
May 19, 2015

#3**+10 **

The plus sign (+) is also a mathematical operator, so you've used two operators. No cookie for you!

Guest May 20, 2015

#4**+10 **

He didn't say * only* one mathematical operator, so it means I can use two ones.

And, if you're so smart **Anonymous**, find a way you can do it using *one *mathematical operator.

Good luck !

I found two other ways (the second is a little bit tricky, since a 8 is formed by a 0 put atop another 0)

[(0!+0!)(0!+0!)+0!]!=[(1+1)(1+1)+1]!=(4+1)!=5!=120

$$({\sqrt{({\sqrt{{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}}}}){!}{\mathtt{\,\small\textbf+\,}}{\mathtt{0}}{!}}}){!}$$=$$({\sqrt{({\sqrt{{\mathtt{16}}}}){!}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}}}){!}$$=$$({\sqrt{{\mathtt{4}}{!}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}}}){!}$$=$$({\sqrt{{\mathtt{25}}}}){!}$$=5!=120

EinsteinJr
May 20, 2015

#5**+5 **

**"any one mathematical operator" - any one means ONLY one **

That is a quote from the question.

It doesn't matter though - I liked your answer :)

I like you second answer too.

I would like to see anon do it with ony one operator as well LOL

Melody
May 20, 2015

#6**+15 **

You're right **Melody**, when I posted it I realized how stupid my remark was

I found a fourth way :

[(0! + 0!)^{(0! + 0!)} + 0!]!=(2²+1)!=(4+1)!=5!=120

But it seems to be impossible to do with only *one *symbol.

EinsteinJr
May 20, 2015

#7**+5 **

It wasn't that stupid - I can understand your annoyance.

You have presented some really clever answers there :)

Melody
May 20, 2015

#9**+5 **

Morgan Tud’s solutions:

web2.0calc . com /questions/a-question-you-can-answer#r6

Technically his second answer is only two operators because “NOT” is a logical operator.

You still don’t get a cookie!

Guest May 20, 2015

#10**+5 **

Then nobody will get a cookie, because it is impossible to do with * only one *operator.

And I don't give a d**n if I don't get a cookie, since I have got a full pack.

EinsteinJr
May 20, 2015

#13**+5 **

Is that why you give them away?

The one you gave CPhill looked like it had roach droppings on it.

Guest May 20, 2015

#16**+10 **

The first answer [cos(0)+cos(0)+cos(0)+cos(0)+cos(0)]! is right since cos(0)=1, but the second one is wrong (not(0)=-1 so [not(0)+not(0)+not(0)+not(0)+not(0)]!=(-1-1-1-1-1)!=(-5)!=MATH ERROR)

EinsteinJr
May 21, 2015