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# I know GFB is similar to CHB, but how do you find GF?

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In the figure below, isosceles triangle ABC with base AB has altitude CH = 24 cm, DE = GF, HF = 12 cm, and FB = 6 cm. find area of CDEFG Apr 21, 2021

#2
+3 By AA similarity, △GFB is similar to △CHB, just as you said This means we can make the following equation:

GF / FB  =  CH / HB

Now we can substitute  6  for  FB,  24 for  CH,  and  18  for HB

GF / 6   =   24 / 18

Multiply both sides of the equation by  6

GF   =   (24 / 18)  *  6

Simplify the right side of the equation

GF   =   8

Now we can find the area of  △GFB

area of △GFB   =   (1/2) * FB * GF   =   (1/2) * 6 * 8   =   24

We can see that because the left side of the big triangle is symmetrical to the right side, △GFB is congruent to  △DEA. (We can also say that since  m∠GBF = m∠DAE,    m∠GFB = m∠DEA,   and  DE = GF,  by AAS,  △GFB ≅  △DEA)

This means the area of △DEA is also 24 sq cm

Now we can find the area of △ABC.

area of △ABC  =  (1/2) * AB * CH  =  (1/2) * (2 * 18) * (24)  =  432

Now we can find the area of CDEFG.

area of CDEFG   =   area of △ABC  -  area of △GFB  -  area of △DEA

area of CDEFG   =   432  -  24  -  24

area of CDEFG   =   384   (and that is in sq cm)

Apr 21, 2021

#1
+1

Hello :))

I'm so obsessed with taylor swift rn.

So CHB = CHA (triangles are similar)

So we can just find FHCG and multiply by 2.

CHB = 24*12/2 = 144

GFB/CHB = 6/24

So CHFG = 108

108*2 = 216

=^._.^=

Apr 21, 2021
#3
+2

i like all songs- hardcore swiftie here😭

wbu?

tayIorswift13  Apr 21, 2021
#5
+2

oh no, it looks like I messed up.

hectitar is completly right.

I love taylor swift :DD

Like, I know all her songs by heart.

My favorites are enchated, all too well, blank space, long live, mr perfectly fine, love story, champagne problems, you are in love, there are just too many to name.

=^._.^=

catmg  Apr 21, 2021
#2
+3 By AA similarity, △GFB is similar to △CHB, just as you said This means we can make the following equation:

GF / FB  =  CH / HB

Now we can substitute  6  for  FB,  24 for  CH,  and  18  for HB

GF / 6   =   24 / 18

Multiply both sides of the equation by  6

GF   =   (24 / 18)  *  6

Simplify the right side of the equation

GF   =   8

Now we can find the area of  △GFB

area of △GFB   =   (1/2) * FB * GF   =   (1/2) * 6 * 8   =   24

We can see that because the left side of the big triangle is symmetrical to the right side, △GFB is congruent to  △DEA. (We can also say that since  m∠GBF = m∠DAE,    m∠GFB = m∠DEA,   and  DE = GF,  by AAS,  △GFB ≅  △DEA)

This means the area of △DEA is also 24 sq cm

Now we can find the area of △ABC.

area of △ABC  =  (1/2) * AB * CH  =  (1/2) * (2 * 18) * (24)  =  432

Now we can find the area of CDEFG.

area of CDEFG   =   area of △ABC  -  area of △GFB  -  area of △DEA

area of CDEFG   =   432  -  24  -  24

area of CDEFG   =   384   (and that is in sq cm)

hectictar Apr 21, 2021
#4
+2

thank you!

tayIorswift13  Apr 21, 2021