How many subsets of the set \(\{1,2,3,4, 5, 6, 7, 8, 9, 10\}\) contain the number 5?

Guest May 6, 2019

#1**+2 **

There are 2^10 different subsets in the original set.

Now let us just subtract subsets without a 5

Let us just pretend you have set without a 5

So {1 2 3 4 6 7 8 9 10} Is your new set

So how many subsets can you make from that?

2^9 subsets

2^10 - 2^9 = **512 different subsets**

NOTE: 2^10 - 2^9 is NOT 2.

So there you have it! :D:D:D

CalculatorUser May 6, 2019

#2**-3 **

To solve this problem, do this...

There are 10 numbers, so the first term of the expression is 2^10. Then subtract that by 2^9 to find the answer.

2^10 = 1024

2^9 = 512

1024-512 = 512

**There are 512 subsets that do not contain the number 5.**

~~Hypotenuisance

Hypotenuisance May 6, 2019