(x+5)/9 +5 = (7x-10)/6
and
(x+5)/10 +5 = (7x-10)/6
Please don´t just say the answer, write the steps too.
Here is the first one:
Solve for x:
(x + 5)/9 + 5 = (7 x - 10)/6
Put each term in (x + 5)/9 + 5 over the common denominator 9: (x + 5)/9 + 5 = 45/9 + (x + 5)/9:
45/9 + (x + 5)/9 = (7 x - 10)/6
45/9 + (x + 5)/9 = ((x + 5) + 45)/9:
(x + 5 + 45)/9 = (7 x - 10)/6
Grouping like terms, x + 5 + 45 = x + (45 + 5):
(x + (45 + 5))/9 = (7 x - 10)/6
45 + 5 = 50:
(x + 50)/9 = (7 x - 10)/6
Multiply both sides by 18:
(18 (x + 50))/9 = (18 (7 x - 10))/6
18/9 = (9×2)/9 = 2:
2 (x + 50) = (18 (7 x - 10))/6
18/6 = (6×3)/6 = 3:
2 (x + 50) = 3 (7 x - 10)
Expand out terms of the left hand side:
2 x + 100 = 3 (7 x - 10)
Expand out terms of the right hand side:
2 x + 100 = 21 x - 30
Subtract 21 x from both sides:
(2 x - 21 x) + 100 = (21 x - 21 x) - 30
2 x - 21 x = -19 x:
-19 x + 100 = (21 x - 21 x) - 30
21 x - 21 x = 0:
100 - 19 x = -30
Subtract 100 from both sides:
(100 - 100) - 19 x = -100 - 30
100 - 100 = 0:
-19 x = -30 - 100
-30 - 100 = -130:
-19 x = -130
Divide both sides of -19 x = -130 by -19:
(-19 x)/(-19) = (-130)/(-19)
(-19)/(-19) = 1:
x = (-130)/(-19)
Multiply numerator and denominator of (-130)/(-19) by -1:
x = 130/19
Here is the second one:
Solve for x:
(x + 5)/10 + 5 = (7 x - 10)/6
Put each term in (x + 5)/10 + 5 over the common denominator 10: (x + 5)/10 + 5 = 50/10 + (x + 5)/10:
50/10 + (x + 5)/10 = (7 x - 10)/6
50/10 + (x + 5)/10 = ((x + 5) + 50)/10:
(x + 5 + 50)/10 = (7 x - 10)/6
Grouping like terms, x + 5 + 50 = x + (50 + 5):
(x + (50 + 5))/10 = (7 x - 10)/6
50 + 5 = 55:
(x + 55)/10 = (7 x - 10)/6
Multiply both sides by 30:
(30 (x + 55))/10 = (30 (7 x - 10))/6
30/10 = (10×3)/10 = 3:
3 (x + 55) = (30 (7 x - 10))/6
30/6 = (6×5)/6 = 5:
3 (x + 55) = 5 (7 x - 10)
Expand out terms of the left hand side:
3 x + 165 = 5 (7 x - 10)
Expand out terms of the right hand side:
3 x + 165 = 35 x - 50
Subtract 35 x from both sides:
(3 x - 35 x) + 165 = (35 x - 35 x) - 50
3 x - 35 x = -32 x:
-32 x + 165 = (35 x - 35 x) - 50
35 x - 35 x = 0:
165 - 32 x = -50
Subtract 165 from both sides:
(165 - 165) - 32 x = -165 - 50
165 - 165 = 0:
-32 x = -50 - 165
-50 - 165 = -215:
-32 x = -215
Divide both sides of -32 x = -215 by -32:
(-32 x)/(-32) = (-215)/(-32)
(-32)/(-32) = 1:
x = (-215)/(-32)
Multiply numerator and denominator of (-215)/(-32) by -1:
x = 215/32
Step one is simplifying the equatation!
(x+5/9)+5 = (7x-10/6)
x + 5/9 + 5 = 7x − 10/6
x + 5/9 + 5 = 7x + −5/3
x + 50/9 = 7x + −5/3
Step two is subtracting 7x from both sides
−6x + 50/9 −7x = −5/3
Step three is subtracting 50/9 from both sides
−6x = −65/9
Step four is dividing both sides by −6
−6x/−6 =−65/9/−6
x = 65/54
Now the second one! First we simplify the equatation.
x + 1/2 + 5 = 7x + −5/3
x + 11/2 = 7x + −5/3
Step two is to subtract 7x from both sides
−6x + 11/2 = −5/3
Step three is subtracting 11/2 from both sides
(−6x + 11/2 − 11/2 = −5/3 − 11/2)
−6x = −43/6
Now we divide both sides by −6
−6x/−6 = −43/6/−6
x = 43/36
Here is the first one:
Solve for x:
(x + 5)/9 + 5 = (7 x - 10)/6
Put each term in (x + 5)/9 + 5 over the common denominator 9: (x + 5)/9 + 5 = 45/9 + (x + 5)/9:
45/9 + (x + 5)/9 = (7 x - 10)/6
45/9 + (x + 5)/9 = ((x + 5) + 45)/9:
(x + 5 + 45)/9 = (7 x - 10)/6
Grouping like terms, x + 5 + 45 = x + (45 + 5):
(x + (45 + 5))/9 = (7 x - 10)/6
45 + 5 = 50:
(x + 50)/9 = (7 x - 10)/6
Multiply both sides by 18:
(18 (x + 50))/9 = (18 (7 x - 10))/6
18/9 = (9×2)/9 = 2:
2 (x + 50) = (18 (7 x - 10))/6
18/6 = (6×3)/6 = 3:
2 (x + 50) = 3 (7 x - 10)
Expand out terms of the left hand side:
2 x + 100 = 3 (7 x - 10)
Expand out terms of the right hand side:
2 x + 100 = 21 x - 30
Subtract 21 x from both sides:
(2 x - 21 x) + 100 = (21 x - 21 x) - 30
2 x - 21 x = -19 x:
-19 x + 100 = (21 x - 21 x) - 30
21 x - 21 x = 0:
100 - 19 x = -30
Subtract 100 from both sides:
(100 - 100) - 19 x = -100 - 30
100 - 100 = 0:
-19 x = -30 - 100
-30 - 100 = -130:
-19 x = -130
Divide both sides of -19 x = -130 by -19:
(-19 x)/(-19) = (-130)/(-19)
(-19)/(-19) = 1:
x = (-130)/(-19)
Multiply numerator and denominator of (-130)/(-19) by -1:
x = 130/19
Here is the second one:
Solve for x:
(x + 5)/10 + 5 = (7 x - 10)/6
Put each term in (x + 5)/10 + 5 over the common denominator 10: (x + 5)/10 + 5 = 50/10 + (x + 5)/10:
50/10 + (x + 5)/10 = (7 x - 10)/6
50/10 + (x + 5)/10 = ((x + 5) + 50)/10:
(x + 5 + 50)/10 = (7 x - 10)/6
Grouping like terms, x + 5 + 50 = x + (50 + 5):
(x + (50 + 5))/10 = (7 x - 10)/6
50 + 5 = 55:
(x + 55)/10 = (7 x - 10)/6
Multiply both sides by 30:
(30 (x + 55))/10 = (30 (7 x - 10))/6
30/10 = (10×3)/10 = 3:
3 (x + 55) = (30 (7 x - 10))/6
30/6 = (6×5)/6 = 5:
3 (x + 55) = 5 (7 x - 10)
Expand out terms of the left hand side:
3 x + 165 = 5 (7 x - 10)
Expand out terms of the right hand side:
3 x + 165 = 35 x - 50
Subtract 35 x from both sides:
(3 x - 35 x) + 165 = (35 x - 35 x) - 50
3 x - 35 x = -32 x:
-32 x + 165 = (35 x - 35 x) - 50
35 x - 35 x = 0:
165 - 32 x = -50
Subtract 165 from both sides:
(165 - 165) - 32 x = -165 - 50
165 - 165 = 0:
-32 x = -50 - 165
-50 - 165 = -215:
-32 x = -215
Divide both sides of -32 x = -215 by -32:
(-32 x)/(-32) = (-215)/(-32)
(-32)/(-32) = 1:
x = (-215)/(-32)
Multiply numerator and denominator of (-215)/(-32) by -1:
x = 215/32
Here is another presentation for what our guest did. Thanks guest :)
\(\frac{(x+5)}{9} +5 =\frac{ (7x-10)}{6}\)
The lowest common denominator is 18 so multiply every term by 18
That way you will get rid of all the fractions and it will be much easier.
\(\frac{18(x+5)}{9} +18*5 =\frac{18 (7x-10)}{6}\\ \frac{2(x+5)}{1} +90 =\frac{3 (7x-10)}{1}\\ 2(x+5)+90 =3 (7x-10)\\ 2x+10+90 =21x-30\\ 2x+100 =21x-30\\ 130 =19x\\ x=\frac{130}{19}=6\frac{16}{19}\)