I'm not actually sure how to type this out, so I took a screenshot. Does anyone know how to solve this? http://prntscr.com/5a6cz7

Good answer anon although not many calcs do base three so you cannot just plug the numbers in and get an answer.    

I am going to write the question sightly differently

$$\\If\;\;\;y=log_{\textcolor[rgb]{0,1,0}3}3^6\\ then\\ 3^6=\textcolor[rgb]{0,1,0}{3}^y\\\\ $Now it is very easy to see that y=6$\\ $so$\\ log_33^6=6\\\\\\ $Remember: $\quad \boxed{If \quad y=log_ba\quad then \quad a=b^y}\\\\ $ You say this as \qquad y=log a base b$\\\\ $Also remember : $\boxed{\mbox{A log is a power}}$$

The log to base 3 of any number is the power numeral when you express that number as a power of 3.

For example, if we write 9 as  $${{\mathtt{3}}}^{{\mathtt{2}}}$$  then you see the power there is 2, so when we take logs to base 3,

we write log 9 = 2

Summarising, log  $${{\mathtt{3}}}^{{\mathtt{2}}}$$  = 2

so log  $${{\mathtt{3}}}^{{\mathtt{6}}}$$  = ......

what answer do you get? 

If ever you're not sure your answer s right, you can always check using a calculator!