I'm trying to do this question, but I don't know what it means.

"Based on the records for the past several seasons, a sports fan believes the probability the red team wins is 0.55. The fan also believes the probability the blue team wins is 0.60. In a season with 180 games, how many fewer games should the fan expect the red team to win?"

Isn't there more than 100 percent there?

mathguardian23
May 26, 2017

#4**0 **

I am not sure either MG

I think we need more info, there must be more than just the 2 teams in the competition. There is 180 games but I do not know how many ofthem the blue or red team actually plays.

I am probably suppose to assume things but i am not sure what that is.

Sorry i cannot be of more help :(

Melody
May 26, 2017

#5**+1 **

I think that it means that in the season of 180 games, the red team has the probability of winning each game of 0.55, so the expected number of games that the red teams wins is 0.55 x 180 = 99 games.

Since the blue team has a probability of 0.60, the expected number of games that the blue teams wins is 0.60 x 180 = 108.

So, the blue team is expected to win 108 - 99 = 9 more games.

Since the percentages don't refer to the same team, the percentages do not have to add to 100.

geno3141
May 26, 2017

#6**0 **

Hi Geno,

This still does not make sense to me.

Ther must be more teams playing or else the percentages do have to add to 100% and if other teams are playing and there are 180 games in total then no team will actually get to play 180 games will they.

So like i said, id does not make sense to me :/

Melody
May 27, 2017