I'm really sorry for all these geom questions!! Last one I promise!! Thanks guys!

I don't see a pic for 10 but I'm pretty sure we have an inscribed right angle CMD with C and D being the diameter endpoints....

The diameter length, CD    =    sqrt  ( CM^2  + MD^2)  =

sqrt  (9^2 + 12^2)  = 

sqrt (81  + 144)  =  sqrt  (225)   =  15

OM  will  form a radius  = (1/2)CD  = 7.5

18....Proof

Since LA is perp. to OK   and LD is perp. to OM.....angles LAO  and LDO  are right angles

And since arc KL  is congruent to arc ML, then central angle KOL = central angle MOL  (central angles intercepting equal arcs are themselves equal)

And by the reflexive property,  LO  = LO

So.......by AAS.......triangle LAO is congruent to triangle LDO

To post the pic just open the image tab and past the URL in.

It is super easy!

Huh? I could not read javascript. Sorry guys.