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The region between the graph of y=f(x) and the x-axis, shaded in this figure, has an area of 10 square units. What is the area between the graph of y=f(x+2) and the x-axis?

The region between the graph of y=f(x) and the x-axis, shaded in this figure, has an area of 10 square units. What is the area between the graph of y=6f(x-6) and the x-axis?

The region between the graph of  y=f(x) and the x-axis, shaded in this figure, has an area of 10 square units. What is the area between the graph of  y=f/2(-x) and the x-axis?

i don't understand how to approach these questions at all

 

 Sep 29, 2019
edited by Oofrence  Sep 29, 2019
edited by Oofrence  Sep 29, 2019
 #1
avatar+177 
+1

never mind, i found out how ridiculously easy this was. Sorry

 Sep 29, 2019
 #2
avatar+105700 
+2

It would have been nice if you had included the answers. Some people may be trying to learn from your question AND the answer.

Melody  Sep 30, 2019
 #3
avatar+177 
+5

Okay.

For number 1, you aren't modifying the shape at all, and only shifting it to the left, so the area is still \(10\)

For number 2, you are enlarging the shape by 6 times, so the area is 6 x 10 = \(60\). You don't need to worry about the x-6 because that is only shifting the shape to the right by 6 units, and not modifying the shape itself

For number 3, you are decreasing the shape 2 times, so the area is 10 / 2 = \(5\). Just like the question before, you don't need to worry about the -x because it is simply creating the reflection of the shape, preserving the area of the shape itself.

Oofrence  Sep 30, 2019
 #4
avatar+2417 
+3

Thanks!

CalculatorUser  Sep 30, 2019
 #5
avatar+105700 
+1

Oofrence,

Thanks for posting this question and answer.

It was an excellent one for people to learn from.

 Sep 30, 2019

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