Two motorcycles are traveling at speeds of 120 kilometers per hour and 90 kilometers per hour respectively. If the faster one travels for 4 hours longer than the slower one and also goes twice as far, how far did the slow one travel?

joebob  Nov 25, 2017

Let the time of the slower bike =t
The time of the faster bike =t + 4
Distance=Time x rate(speed)
2(90t) =120[t + 4], solve for t
t=8 hours
8 x 90 =720 km - the distance traveled by the slower bike.
120 x[8 + 4] =1,440 km - the distance traveled by the faster bike.

Guest Nov 25, 2017
edited by Guest  Nov 25, 2017

Nice work guest :)

Melody  Nov 25, 2017

17 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.