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What is the sum of all of the four-digit positive integers that can be written with the digits 1, 2, 3 and 4 if each digit must be used exactly once in each four-digit positive integer?

 Sep 11, 2020
 #1
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The sum is (1 + 2 + 3 + 4)*1111*8 = 88880.

 Sep 11, 2020
 #2
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There are 4! =24 such numbers:

 

1234 , 1243 , 1324 , 1342 , 1423 , 1432 , 2134 , 2143 , 2314 , 2341 , 2413 , 2431 , 3124 , 3142 , 3214 , 3241 , 3412 , 3421 , 4123 , 4132 , 4213 , 4231 , 4312 , 4321 >>Total =  66,660 - Their total sum

 Sep 11, 2020

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