The positive difference between two consecutive odd perfect squares is 336. Compute the larger of the two squares.
We have \(x\) as the smaller odd number and \(x+2\) as the larger odd number.
Translating this into an equation, we have \((x+2)^2-x^2=336\).
Expanding \((x+2)^2-x^2=4x+4\).
Rewriting, we attain \(4x+4=336, 4x=332\) and \(x=83.\)
So, \(x+2=85\) or \(\boxed{7225}.\)
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