I woule like a proper explaination please! Not just the answer!
In triangle PQR,M is the midpoint of ¯PQ Let X be the point on ¯QR such that ¯PX bisects ∠QPR and let the perpendicular bisector of ¯PQ intersect ¯PX at Y If PQ=36 and MY=8 then find the area of triangle PYR.
Here are the steps to solve the problem:
Since M is the midpoint of PQ, then QM = 18.
Since PX bisects angle QPR, then PX = QR/2 = 19.
Since Y is on the perpendicular bisector of PQ, then PY = QY = 18.
Since MY = 8, then PY = 18 - 8 = 10.
Since PX = 19 and PY = 10, then triangle PXY is a 9-10-11 right triangle.
Since the perpendicular bisector of PQ intersects PX at Y, then PY is an altitude of triangle PQR.
Therefore, the area of triangle PYR is (1/2)(PQ)(PY) = (1/2)(36)(10) = 180.
Therefore, the area of triangle PYR is 180.