Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
94
4
avatar+197 

I woule like a proper explaination please! Not just the answer!



In triangle PQR,M is the midpoint of ¯PQ Let X be the point on ¯QR such that ¯PX bisects QPR and let the perpendicular bisector of ¯PQ intersect ¯PX at Y If  PQ=36 and MY=8 then find the area of triangle PYR.

 Jul 5, 2023
 #1
avatar
-1

Here are the steps to solve the problem:

Since M is the midpoint of PQ, then QM = 18.

Since PX bisects angle QPR, then PX = QR/2 = 19.

Since Y is on the perpendicular bisector of PQ, then PY = QY = 18.

Since MY = 8, then PY = 18 - 8 = 10.

Since PX = 19 and PY = 10, then triangle PXY is a 9-10-11 right triangle.

Since the perpendicular bisector of PQ intersects PX at Y, then PY is an altitude of triangle PQR.

Therefore, the area of triangle PYR is (1/2)(PQ)(PY) = (1/2)(36)(10) = 180.

Therefore, the area of triangle PYR is 180.

 Jul 5, 2023
 #4
avatar
0

 

 

>>>>> is a 9-10-11 right triangle <<<<<  

 

I don't know about the rest of the answer, but 9-10-11 is not a right triangle.  

Guest Jul 5, 2023
 #2
avatar+197 
0

that wasn't correct...

 Jul 5, 2023
 #3
avatar+197 
+2

nvm...i found the answer...it's 88

 Jul 5, 2023

0 Online Users