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# I need help finding the angle of a right sided triangle.

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1140
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I need help finding the angle of a right sided triangle.

Hypotenuse = 23

I need the angle between them.

math
Aug 21, 2014

#2
+5

Remember:

Some Old Hags,         Sin=Opp/Hyp

You have adj and hyp so the ratio is Cos.

Now if you want to find an angle you must use inverse trig. That is  $$Cos^{-1}$$  but the Web2 site calc does not have that.  Arc tan is exactly the same thing!  So use acos $$\underset{\,\,\,\,^{{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{13}}}{{\mathtt{23}}}}\right)} = {\mathtt{55.582\: \!611\: \!289\: \!558^{\circ}}}$$

Aug 21, 2014

#1
+5

You would need to use cos theta since cos theta = adjacent/hypotenuse

cos theta = 13/23

cos^-1(13/23) = theta

theta = 55.6o.

Aug 21, 2014
#2
+5

Remember:

Some Old Hags,         Sin=Opp/Hyp

You have adj and hyp so the ratio is Cos.

Now if you want to find an angle you must use inverse trig. That is  $$Cos^{-1}$$  but the Web2 site calc does not have that.  Arc tan is exactly the same thing!  So use acos $$\underset{\,\,\,\,^{{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{13}}}{{\mathtt{23}}}}\right)} = {\mathtt{55.582\: \!611\: \!289\: \!558^{\circ}}}$$