10. Identify the initial amount and the growth rate of the following:
Y = 250 (1+0.2)t
11. Identify the initial amount and the growth rate of the following:
Y = 9.8 (1.35)t
+532 10)
Assuming t is a time unit.
The initial amount is when t = 0, so it is 250 * 1 = 250. The growth rate is how much the amount goes up by for every increase of 1 in t. This is 1.2, because that is the part being affected by t. So, it is 120% factor or an increase of 20% each time.
11)
Using the same logic, we plug in 0 for t to get 9.8 as the initial amount. The growth rate is just 135% factor, or 35% more each time, because 1.35 is the base of the exponent.
+532 10)
Assuming t is a time unit.
The initial amount is when t = 0, so it is 250 * 1 = 250. The growth rate is how much the amount goes up by for every increase of 1 in t. This is 1.2, because that is the part being affected by t. So, it is 120% factor or an increase of 20% each time.
11)
Using the same logic, we plug in 0 for t to get 9.8 as the initial amount. The growth rate is just 135% factor, or 35% more each time, because 1.35 is the base of the exponent.
