The question asks what is the value of y. There is a triangle that has the measurements (2y+20)dg, (5x)dg, and 40dg. I need to solve for the value y. How do I do this, I was a bit confused? I know how to solve for x though, is it similiar or?
The question asks what is the value of y. There is a triangle that has the measurements (2y+20)dg, (5x)dg, and 40dg. I need to solve for the value y. How do I do this, I was a bit confused? I know how to solve for x though, is it similiar or?
(2y+20) + 5x + 40 =180
(2y+20) =5x + 40
Solve the following system:
{60 + 5 x + 2 y = 180 | (equation 1)
2 y + 20 = 5 x + 40 | (equation 2)
Express the system in standard form:
{5 x + 2 y = 120 | (equation 1)
-(5 x) + 2 y = 20 | (equation 2)
Add equation 1 to equation 2:
{5 x + 2 y = 120 | (equation 1)
0 x+4 y = 140 | (equation 2)
Divide equation 2 by 4:
{5 x + 2 y = 120 | (equation 1)
0 x+y = 35 | (equation 2)
Subtract 2 × (equation 2) from equation 1:
{5 x+0 y = 50 | (equation 1)
0 x+y = 35 | (equation 2)
Divide equation 1 by 5:
{x+0 y = 10 | (equation 1)
0 x+y = 35 | (equation 2)
Collect results:
Answer: |x = 10 and y = 35
+37091 I am confused.....
Can you tell me where you came up with (2y+20) = 5x +40 ???
I think you could make the assumption that (2y+20) + 40 = 5x (reulting in y=25 and x=14) ???
