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Camy made a list of every possible distinct five-digit positive integer that can be formed using each of the digits 1, 3, 4, 5 and 9 exactly once in each integer. What is the sum of the integers on Camy's list?

ANotSmartPerson Nov 8, 2018

#1**+1 **

Here is my 'shot' at it

there are

5 x 4 x 3 x 2 x 1 = 120 possible numbers,

so each didgit must appear in each position 120/5 = 24 times

So each position of the 5 digit numbers must sum up to

24(1) + 24(3) + 24(4) + 24(5) + 24(9) = 24(1+3+4+5+9) = 528

P5 P4 P3 P2 P1

528 528 528 528 528

adding these together (P1 would be 8 carry 52 to P2 etc)

I come up with

5,866,608 (I hope it is corrrect !)

ElectricPavlov Nov 8, 2018