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i need help solving this problem. what is the power of x. (squareroot of x over the fifth root of x) all to the power of 1/3

 Aug 19, 2015

Best Answer 

 #1
avatar+17746 
+5

Square root of x  --->   x1/2

Fifth root of x  --->   x1/5

( x1/2 / x1/5 )1/3

Since  inside the parentheses is a division problem, subtract the exponents:

            1/2 - 1/5  =  3/10:

=  ( x3/10 )1/3

Since this is an exponent to an exponent, multiply the exponents:

=  x3/10 x 1/3  =  x1/10     or the tenth root of x

 Aug 19, 2015
 #1
avatar+17746 
+5
Best Answer

Square root of x  --->   x1/2

Fifth root of x  --->   x1/5

( x1/2 / x1/5 )1/3

Since  inside the parentheses is a division problem, subtract the exponents:

            1/2 - 1/5  =  3/10:

=  ( x3/10 )1/3

Since this is an exponent to an exponent, multiply the exponents:

=  x3/10 x 1/3  =  x1/10     or the tenth root of x

geno3141 Aug 19, 2015

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