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If w2 and z3 are inversely proportional and w=3 when z=12, what is z when w=6?

 Jun 27, 2021

Best Answer 

 #3
avatar+35057 
+3

w^2 = k / z^3       where k is the proprtionality constant

 

3^2 = k / 12^3     shows k = 15552

 

w^2 = 15552/z^3      when w = 6       z = 7.5595

 Jun 27, 2021
 #1
avatar+2244 
+1

w^3*z^3 = x

3^3 * 12^3 = 46656

x = 46656

w^3 * 6^3 = 46656

w^3 = 216

w = 6

 

=^._.^=

 Jun 27, 2021
 #2
avatar+306 
+2

I think you are supposed to find z not w...

calvinbun  Jun 27, 2021
 #4
avatar+2244 
+1

Oops, replaced the wrong variable and read the question wrong. 

3^2 * 12^3 = k

6^2 * z^3 = k

3^2 * 12^3 = 6^2 * z^3

z = 7.5595

 

Nice job EP. :)))

 

=^._.^=

catmg  Jun 27, 2021
 #3
avatar+35057 
+3
Best Answer

w^2 = k / z^3       where k is the proprtionality constant

 

3^2 = k / 12^3     shows k = 15552

 

w^2 = 15552/z^3      when w = 6       z = 7.5595

ElectricPavlov Jun 27, 2021

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