+379 If w2 and z3 are inversely proportional and w=3 when z=12, what is z when w=6?
+37163 w^2 = k / z^3 where k is the proprtionality constant
3^2 = k / 12^3 shows k = 15552
w^2 = 15552/z^3 when w = 6 z = 7.5595
+2407 w^3*z^3 = x
3^3 * 12^3 = 46656
x = 46656
w^3 * 6^3 = 46656
w^3 = 216
w = 6
=^._.^=
+37163 w^2 = k / z^3 where k is the proprtionality constant
3^2 = k / 12^3 shows k = 15552
w^2 = 15552/z^3 when w = 6 z = 7.5595
