If w^{2} and z^{3} are inversely proportional and w=3 when z=12, what is z when w=6?

calvinbun Jun 27, 2021

#3**+4 **

w^2 = k / z^3 where k is the proprtionality constant

3^2 = k / 12^3 shows k = 15552

w^2 = 15552/z^3 when w = 6 z = 7.5595

ElectricPavlov Jun 27, 2021

#1**+1 **

w^3*z^3 = x

3^3 * 12^3 = 46656

x = 46656

w^3 * 6^3 = 46656

w^3 = 216

w = 6

=^._.^=

catmg Jun 27, 2021

#3**+4 **

Best Answer

w^2 = k / z^3 where k is the proprtionality constant

3^2 = k / 12^3 shows k = 15552

w^2 = 15552/z^3 when w = 6 z = 7.5595

ElectricPavlov Jun 27, 2021