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The height (in meters) of a shot cannonball follows a trajectory given by\(h(t) = -4.9t^2 + 14t - 0.4\)  at time t (in seconds). As an improper fraction, for how long is the cannonball above a height of 6 meters?

 Jul 17, 2019
 #1
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solve the equation. 

 

\(6 = -4.9t^2 + 14t - 0.4\)

 

Hint :  it is a quadratic.  Take it all to one side and use the quadratic formula.

 

 

 

The height will be above 6m between the time periods.

 

And for peats sake no one rush in a give a full answer. 

This forum is supposed to help people learn!

 

Asker if you have problems you can show what you have done and maybe we will help you more.

 Jul 17, 2019

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