The height (in meters) of a shot cannonball follows a trajectory given by\(h(t) = -4.9t^2 + 14t - 0.4\) at time t (in seconds). As an improper fraction, for how long is the cannonball above a height of 6 meters?

Guest Jul 17, 2019

#1**+1 **

solve the equation.

\(6 = -4.9t^2 + 14t - 0.4\)

**Hint : it is a quadratic. Take it all to one side and use the quadratic formula.**

The height will be above 6m between the time periods.

**And for peats sake no one rush in a give a full answer.**

**This forum is supposed to help people learn!**

Asker if you have problems you can show what you have done and maybe we will help you more.

Melody Jul 17, 2019