Hello my lovely community, I have this equation :
0 = I1/r - I2/r+d
By the way the 1 at I1 is an index. Same goes for I2.
I want to solve this equation for r but I am helpless :(
Could anyone help me and show it to me step by step ?
Is the equation
0 = I^(1/r) - I^(2/r) + d ????
Or is it
0 = I^1 / r + I^(2) / r + d ????
Oh...OK....I understand now
We have that
0 = I1 / r + I2 / r + d subtract d from both sides
-d = I1 / r + I2 / r note that the right side can be written as
-d = [ I1 + I2 ] / r multiply both sides by r
-rd = I1 + I2 divide both sides by -d
r = [ I1 + I2 ] / -d
r = - [ I1 + I2 ] / d
P.S. ......if the "d" is supposed to be a part of the second denominator, we have
0 = I1 / r + I2 / (r + d) get a common denominator
0 = [ I1 ( r + d) + I2 r ] / [ r (r + d) ] multiply boh sides by [ r (r + d) ]
0 * [ r (r + d) ] = [ I1 ( r + d) + I2 r ]
0 = [ I1 ( r + d) + I2 r ] simplify
0 = I1 r + I1d + I2 r subtract I1d from both sides
- I1d = I1 r + I2 r factor the right side
- I1d = r [ I1 + I2 ] divide both sides by [ I1 + I2 ]
- I1d / [ I1 + I2 ] = r