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0
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13
avatar+95 

y= 1/2x+3

y=-1/4x-3

 Aug 27, 2014

Best Answer 

 #5
avatar+129840 
+10

OK......let's multiply the second equation by -1 all the way through...so we have....

  -[ y = -(1/4)x -3 ]  →  -y = (1/4)x +3

Now add this equation to the first one......so we have

  y = (1/2)x +3

-y = (1/4)x +3

-------------------

0 = (3/4)x + 6

Subtract 6 from both sides

-6 = (3/4)x     multiply both sides  by 4/3

-24/3 = x = -8

Now......just replace this value in one of the equations to get "y"...I''ll use the ffirst one...

y = -(1/2)(-8) + 3

y = -4 + 3

y = -1

And there's the solution !!!

Hope that helps trQ  !!!!

-----------------------------------------------------------------------------------------------------------------------

Thanks again, ND....my eyes aren't what they once were!!!! (LOL!!!)

 

  

 Aug 27, 2014
 #1
avatar+129840 
0

Do you want to solve this or graph the equations ???

 

 

  

 Aug 27, 2014
 #2
avatar+95 
0

Solve by graphing

 Aug 27, 2014
 #3
avatar+129840 
+5

See the solution here:

 

https://www.desmos.com/calculator/ax3p5l5z7s

 Just click on the intersection point of the ttwo graphs...the solution is (-8, -1)

I'm not at my home computer, trQ, so I hope this works !!!

 

  

 Aug 27, 2014
 #4
avatar+95 
0

Could You possibly get the coordinates, oh sorry. I meant solve not solve by graphing. Sorry for the confusiong.

 Aug 27, 2014
 #5
avatar+129840 
+10
Best Answer

OK......let's multiply the second equation by -1 all the way through...so we have....

  -[ y = -(1/4)x -3 ]  →  -y = (1/4)x +3

Now add this equation to the first one......so we have

  y = (1/2)x +3

-y = (1/4)x +3

-------------------

0 = (3/4)x + 6

Subtract 6 from both sides

-6 = (3/4)x     multiply both sides  by 4/3

-24/3 = x = -8

Now......just replace this value in one of the equations to get "y"...I''ll use the ffirst one...

y = -(1/2)(-8) + 3

y = -4 + 3

y = -1

And there's the solution !!!

Hope that helps trQ  !!!!

-----------------------------------------------------------------------------------------------------------------------

Thanks again, ND....my eyes aren't what they once were!!!! (LOL!!!)

 

  

CPhill Aug 27, 2014
 #6
avatar+3454 
0

CPhill, I think you misinterpreted the second equation of a line. :)

You had 

$$y=\frac{1}{4}x-3$$

but it looks like it is really 

$$y=-\frac{1}{4}x-3$$

 

In this case, the second line would be going in the opposite direction, and would look something like this: https://www.desmos.com/calculator/fkwxfhm3gd

 Aug 27, 2014
 #7
avatar+129840 
0

Thanks ND...I'll go back and edit my answer...I missed that minus sign.....!!!

 

  

 Aug 27, 2014
 #8
avatar+3454 
0

No prob. Those minus signs can be tricky. :)

 Aug 27, 2014
 #9
avatar+129840 
0

Yeah...particularly when you've lost your seeing-eye dog like I have !!!!

 

  

 Aug 27, 2014
 #10
avatar+95 
0

  So may i ask what the answer is?

 Aug 27, 2014
 #11
avatar+95 
0

Oh lol, nvm.

 Aug 27, 2014
 #12
avatar+129840 
0

Sorry...I kinda' missed that minus sign....I went back and corrected my answer....thanks to NinjaDevo for bailing me out !!!

I assume you're OK with it, now???

 

  

 Aug 27, 2014
 #13
avatar+95 
0

Yes sir. Thank You for your help. (P.S. Im about to ask more questions so be ready/prepared) 

 Aug 27, 2014

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