OK......let's multiply the second equation by -1 all the way through...so we have....
-[ y = -(1/4)x -3 ] → -y = (1/4)x +3
Now add this equation to the first one......so we have
y = (1/2)x +3
-y = (1/4)x +3
-------------------
0 = (3/4)x + 6
Subtract 6 from both sides
-6 = (3/4)x multiply both sides by 4/3
-24/3 = x = -8
Now......just replace this value in one of the equations to get "y"...I''ll use the ffirst one...
y = -(1/2)(-8) + 3
y = -4 + 3
y = -1
And there's the solution !!!
Hope that helps trQ !!!!
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Thanks again, ND....my eyes aren't what they once were!!!! (LOL!!!)
See the solution here:
https://www.desmos.com/calculator/ax3p5l5z7s
Just click on the intersection point of the ttwo graphs...the solution is (-8, -1)
I'm not at my home computer, trQ, so I hope this works !!!
Could You possibly get the coordinates, oh sorry. I meant solve not solve by graphing. Sorry for the confusiong.
OK......let's multiply the second equation by -1 all the way through...so we have....
-[ y = -(1/4)x -3 ] → -y = (1/4)x +3
Now add this equation to the first one......so we have
y = (1/2)x +3
-y = (1/4)x +3
-------------------
0 = (3/4)x + 6
Subtract 6 from both sides
-6 = (3/4)x multiply both sides by 4/3
-24/3 = x = -8
Now......just replace this value in one of the equations to get "y"...I''ll use the ffirst one...
y = -(1/2)(-8) + 3
y = -4 + 3
y = -1
And there's the solution !!!
Hope that helps trQ !!!!
-----------------------------------------------------------------------------------------------------------------------
Thanks again, ND....my eyes aren't what they once were!!!! (LOL!!!)
CPhill, I think you misinterpreted the second equation of a line. :)
You had
$$y=\frac{1}{4}x-3$$
but it looks like it is really
$$y=-\frac{1}{4}x-3$$
In this case, the second line would be going in the opposite direction, and would look something like this: https://www.desmos.com/calculator/fkwxfhm3gd
Thanks ND...I'll go back and edit my answer...I missed that minus sign.....!!!
Sorry...I kinda' missed that minus sign....I went back and corrected my answer....thanks to NinjaDevo for bailing me out !!!
I assume you're OK with it, now???
Yes sir. Thank You for your help. (P.S. Im about to ask more questions so be ready/prepared)