We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
141
1
avatar+80 

When the expression -2x^2-20x-53 is written in the form a(x+d)^2+e, where a, d, and e are constants, then what is the sum a+d+e?

 Dec 26, 2018
edited by Guest  Dec 26, 2018
 #1
avatar+103131 
+1

When the expression -2x^2-20x-53 is written in the form a(x+d)^2+e, where a, d, and e are constants, then what is the sum a+d+e?

 

 

-2x^2 - 20x - 53     factor out the -2

 

-2 (x^2 + 10x + 53/2 )

 

Take 1/2 of 10 = 5...square it = 25.....add and subtract it within the parentheses

 

-2 (x^2 + 10x + 25  +  53/2 - 25 )     factor the first 3 terms in the parentheses.....

 

-2 [ (x + 5)^2    + 53/2 - 50/2 ]

 

-2  [ (x + 5)^2 +  3/2 ]         apply the -2 across the terms in the parentheses

 

-2 (x + 5)^2  - 3

 

a = - 2

d = 5

e = -3

 

And their sum  is   0   !!!

 

 

 

cool cool cool

 Dec 26, 2018

12 Online Users

avatar
avatar