+80 When the expression -2x^2-20x-53 is written in the form a(x+d)^2+e, where a, d, and e are constants, then what is the sum a+d+e?
+129852 When the expression -2x^2-20x-53 is written in the form a(x+d)^2+e, where a, d, and e are constants, then what is the sum a+d+e?
-2x^2 - 20x - 53 factor out the -2
-2 (x^2 + 10x + 53/2 )
Take 1/2 of 10 = 5...square it = 25.....add and subtract it within the parentheses
-2 (x^2 + 10x + 25 + 53/2 - 25 ) factor the first 3 terms in the parentheses.....
-2 [ (x + 5)^2 + 53/2 - 50/2 ]
-2 [ (x + 5)^2 + 3/2 ] apply the -2 across the terms in the parentheses
-2 (x + 5)^2 - 3
a = - 2
d = 5
e = -3
And their sum is 0 !!!
