Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
940
1
avatar+283 

Suppose a function f(x) has domain (-\infty,\infty) and range [-11,3]. If we define a new function g(x) by g(x) = f(6x)+1, then what is the range of g(x)? Express your answer in interval notation.

 Apr 5, 2019
edited by Guest  Apr 5, 2019
 #1
avatar+6252 
+2

f(6x) has the same range as f(x)f(6x)+1 shifts the range of f(x) 1 unit in the positive direction so that the range of g(x)=f(6x)+1 is [10,4]

.
 Apr 6, 2019

1 Online Users