I would type this out, but you need to see something I cannot type. :)
I actually already have this answer!! Haha!! I figured it out!! Thanks though!
Thank you for presenting your question nicely :)
Don't worry about it, LF....as long as I can see it, the form doesn't matter
We can write the numerator as x^(5/2) y ^(3/2)
And the denominator is x^(2) y ^(3)
So....using an / am = an-m we have
x^(5/2 - 2) * y^ (3/2 - 3) =
x^(5/2- 4/2) * y^(3/2 - 6/2) =
x^(1/2) * y ( -3/2) ⇒ "B"