I need help with understanding this!

I actually already have this answer!! Haha!! I figured it out!! Thanks though! 

Thank you for presenting your question nicely :)

Don't worry about it, LF....as long as I can see it, the form doesn't matter

We can write the numerator  as  x^(5/2)  y ^(3/2)

And the denominator is x^(2) y ^(3)

So....using   aⁿ / a^m  =  a^n-m   we have

x^(5/2 - 2)  *  y^ (3/2 - 3)   =

x^(5/2- 4/2) * y^(3/2 - 6/2)  =

x^(1/2) * y ( -3/2) ⇒   "B"