Jake and Don had the same amount of money at first. When Jake gave Don $36, 50% of the amount of money Jake had left was the same as 75% of what Don had left. How much did they have in total at first?

Soyoxxommm Apr 20, 2021

#1**+1 **

This question is inappopriate as you've mixed up the names in the second line.. right question is-

Jake and Don had the same amount of money at first. When Jake gave Don $36, 50% of the amount of money

Donhad left was the same as 75% of whatJakehad left. How much did they have in total at first?

Here's the solution-

Let us assume that Jake and Don had \($x\) at first.

Now, Jake gave $36 to Don

∴ Amt. left with Jake = \(x-36\)

Amt. left with Don = \(x+36\)

According to ques.

50% of \((x+36)\) = 75% of \((x-36)\)

⇒\(50(x+36) = 75(x-36)\)

⇒\(50x+1800=75x-2700\)

⇒\(25x=3600\)

⇒\(x=144\)

∴ Initially Jake and Don had **$144 **with them.

*Hope this helps :) *

amygdaleon305 Apr 21, 2021