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Jake and Don had the same amount of money at first. When Jake gave Don $36, 50% of the amount of money Jake had left was the same as 75% of what Don had left. How much did they have in total at first?

 Apr 20, 2021
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This question is inappopriate as you've mixed up the names in the second line.. right question is- 

 

Jake and Don had the same amount of money at first. When Jake gave Don $36, 50% of the amount of money Don had left was the same as 75% of what Jake had left. How much did they have in total at first?

 

Here's the solution- 

 

Let us assume that Jake and Don had \($x\) at first.

 

Now, Jake gave $36 to Don 

∴ Amt. left with Jake = \(x-36\)

Amt. left with Don = \(x+36\)

 

According to ques.

50% of \((x+36)\) = 75% of \((x-36)\)

\(50(x+36) = 75(x-36)\)

\(50x+1800=75x-2700\)

\(25x=3600\)

\(x=144\)

 

∴ Initially Jake and Don had $144 with them.

 

Hope this helps :) 

 Apr 21, 2021
edited by amygdaleon305  Apr 21, 2021

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