+0

# I need help...

0
271
4

Let  $$\alpha$$ and $$\beta$$ be angles such that  is the terminal point for $$a$$ and $$Q$$  is the terminal point for $$\beta$$ . Let $$R, S, T, U$$  be other terminal points below:

Then $$R, S, T, U$$ are the terminal points for the angles $$\alpha+\beta, \beta-\alpha, 2\beta, -\alpha$$  in some order.

$$R, S, T, U$$

Order the terminal pointsto match the angles above.

Mar 28, 2022

#1
+36721
+1

r = b - a

s = a + b

u = 2 b

t = - a

Mar 28, 2022
#2
+1

Hello ElectricPavlov,

Thank you very much for the response, I greatly appreciate your help. Can you please explain your thought process for solving this question? It would really help me in future problems such as this.

Guest Mar 28, 2022
#3
+36721
+2

For clarity, I re-labelled the points   alpha and beta in the diagram below

Now if you look at point R    you can see that it is just point  b   minus the amount of point  a    ......   right?

similarly    point   b    PLUS the maount of point  a     would land you at  S

b   is approximately 145 degrees      2 * 145 = 290 degrees ....which would be point  U

look at point  a     go the same amount in the clockwise direction from the x-axis to get to   -a  ...... this would be point  T

ElectricPavlov  Mar 28, 2022
#4
+1

Thank you ElectricPavlov, it makes sense now.

Mar 28, 2022