Let \(\alpha \) and \(\beta\) be angles such that is the terminal point for \(a \) and \(Q\) is the terminal point for \(\beta \) . Let \(R, S, T, U\) be other terminal points below:
Then \(R, S, T, U\) are the terminal points for the angles \(\alpha+\beta, \beta-\alpha, 2\beta, -\alpha\) in some order.
\(R, S, T, U\)
Order the terminal pointsto match the angles above.
r = b - a
s = a + b
u = 2 b
t = - a
Thank you very much for the response, I greatly appreciate your help. Can you please explain your thought process for solving this question? It would really help me in future problems such as this.
For clarity, I re-labelled the points alpha and beta in the diagram below
Now if you look at point R you can see that it is just point b minus the amount of point a ...... right?
similarly point b PLUS the maount of point a would land you at S
b is approximately 145 degrees 2 * 145 = 290 degrees ....which would be point U
look at point a go the same amount in the clockwise direction from the x-axis to get to -a ...... this would be point T