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I can't figure out this one

Find the Indicated sum

\(\sum_{i=1}^{Infinity} (-\frac{2}{5})^i-1\)

the exponet is soppose to be i-1 

Thank you for your help!! laugh

 Apr 22, 2016

Best Answer 

 #1
avatar+118677 
+10

Hi BlueFire28, it is nice to meet you :)

 

 

I can't figure out this one

Find the Indicated sum

the exponet is soppose to be i-1 

Thank you for your help!! 

 

\(\sum_{i=1}^\infty\;\left(\frac{-2}{5}\right)^{i-1}\\~\\ 1+\frac{-2}{5}+\frac{4}{25}+ \ldots\\ \mbox{This is the sum of a GP and it has a limit since r=-2/5 and |r|<1}\\ S_{\infty}=\frac{a}{1-r}=\frac{1}{1-\;-0.4}=\frac{1}{1.4}=\frac{5}{7}\\ so\\ \sum_{i=1}^\infty\;\left(\frac{-2}{5}\right)^{i-1}=\frac{5}{7}\\~\\ \)

 Apr 23, 2016
 #1
avatar+118677 
+10
Best Answer

Hi BlueFire28, it is nice to meet you :)

 

 

I can't figure out this one

Find the Indicated sum

the exponet is soppose to be i-1 

Thank you for your help!! 

 

\(\sum_{i=1}^\infty\;\left(\frac{-2}{5}\right)^{i-1}\\~\\ 1+\frac{-2}{5}+\frac{4}{25}+ \ldots\\ \mbox{This is the sum of a GP and it has a limit since r=-2/5 and |r|<1}\\ S_{\infty}=\frac{a}{1-r}=\frac{1}{1-\;-0.4}=\frac{1}{1.4}=\frac{5}{7}\\ so\\ \sum_{i=1}^\infty\;\left(\frac{-2}{5}\right)^{i-1}=\frac{5}{7}\\~\\ \)

Melody Apr 23, 2016

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