The quadratic \(2x^2-3x+27\) has two imaginary roots. What is the sum of the squares of these roots? Express your answer as a decimal rounded to the nearest hundredth.
Please help me quick! Thank you! 
+2862 What I would do is use the quadratic formula.
Then add the squares of the roots. You would get a real number.
Here is practice for complex solutions to quadratics if you are having trouble on these types
+128406 2x^2 - 3x + 27
Call the roots a , b
The sum of these roots = - (-3/2) = 3/2
The product of these roots = 27/2
So
a + b = 3/2 (1)
ab = 27/2 (2)
Square both sides of (1)
a^2 + 2ab + b^2 = 9/4
a^2 + b^2 = 9/4 - 2ab sub in (2)
a^2 + b^2 = 9/4 - 2 (27/2)
a^2 + b^2 = 9/4 - 27
a^2 + b^2 = 9/4 - 108/4
a^2 + b^2 = - 99/4 = -24.75
