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Consider the function f(x)=ln(x-3). Find the inverse of f and call this function g(x). Evaluate g(7). Round to 1 decimal place.

Deathstroke_rule  Mar 6, 2017

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 #2
avatar+8772 
+5

Consider the function f(x)=ln(x-3). Find the inverse of f and call this function g(x). Evaluate g(7). Round to 1 decimal place.

laugh

Omi67  Mar 6, 2017
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 #1
avatar+76946 
+5

Write

 

y = ln ( x - 3)     exponentiate both sides

 

e^y  =   e^ [ lh(x - 3) ]

 

e^y  =  x - 3        add 3 to both sides

 

e^y  + 3  =  x       swap x and y

 

e^x  + 3  = y      and for y write  g(x)

 

So

 

g(x)  = e^x + 3

 

And

 

g(7)   =   e^7 + 3  ≈  1099.6

 

 

 

cool cool cool

CPhill  Mar 6, 2017
 #2
avatar+8772 
+5
Best Answer

Consider the function f(x)=ln(x-3). Find the inverse of f and call this function g(x). Evaluate g(7). Round to 1 decimal place.

laugh

Omi67  Mar 6, 2017

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