i need help

The graphing form is:   y - k  =  a(x - h)²   where the vertex is (h, k)  =  (2, 4).

--->   y - 4  =  a(x - 2)²  

To find a, substitute the values of (1, 1) into the above form:

--->   y - 4  =  a(x - 2)²   --->    1 - 4  =  a(1 - 2)²   --->   -3  =  a(-1)²   --->   -3  =  a

So, the equation is:  y - 4  =  -3(x - 2)² 

To get this into the desired form:  y - 4  =  -3(x² - 4x + 4)   --->   y - 4  =  -3x² + 12x - 12

--->   y²  =  -3x² + 12x - 8

Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (1,1).

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