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Let line 1 be the graph of 5x+8y=-9. Line 2 is perpendicular to line 1 and passes through the point (10,10). If line 2 is the graph of the equation y=mx+b, then find. m+b

 Jan 5, 2021

Best Answer 

 #1
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1. First convert from standard form to slope intercept form .

$5x+8y=-9$

$8y=-5x-9$

$y=-5/8-9/8$

$m=-5/8$


2. find other line

Perpendicular lines have negative reciprocal slopes

 

$-5/8 =>8/5$

$y=8/5x+b$

 

From the given information, 

 

$(10)=8/5(10) + b$

$10=16+b$

$b=-6$

 

the line is:

$y=8/5x-6$
therefore 8/5-6=$-22/5$


 

 Jan 5, 2021
 #1
avatar
+1
Best Answer

1. First convert from standard form to slope intercept form .

$5x+8y=-9$

$8y=-5x-9$

$y=-5/8-9/8$

$m=-5/8$


2. find other line

Perpendicular lines have negative reciprocal slopes

 

$-5/8 =>8/5$

$y=8/5x+b$

 

From the given information, 

 

$(10)=8/5(10) + b$

$10=16+b$

$b=-6$

 

the line is:

$y=8/5x-6$
therefore 8/5-6=$-22/5$


 

Guest Jan 5, 2021

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