Real numbers a and b satisfy
a + ab^2 = 250b
a - ab = 0
Enter all possible values of separated by commas.
factoring a from the second equation:
a(1 - b) = 0.
two cases satisfy this: a = 0 or b = 1.
if a = 0, the first equation becomes:
0 = 250b.
so a = 0, b = 0 is one solution.
if b = 1, the first equation becomes:
a + a = 250.
so a = 125, b = 1 is another solution.
solutions are (0,0), (125,1).