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A loudspeaker needs a household voltage of 110 V to push a current of 5 A through its coil. What is the resistance of the loudspeaker?

 Oct 15, 2021
 #1
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A loudspeaker needs a household voltage of 110 V to push a current of 5 A through its coil. What is the resistance of the loudspeaker?    

 

I assume that we're going to neglect the complexities of calculating alternating current versus direct current, and simply go with the standard formula of E = IR.  Voltage = Current x Resistance   They use E for voltage because it stands for Electromotive Force, but I don't know why they use I to represent current, maybe it's from Latin or something like that.  We're also going to neglect the inconvenient fact that it requires a varying direct current to drive a speaker.     

 

                                                                          E  =  IR  

 

Since we're looking for resistance, 

we want to isolate R on one side of 

the equation, so divide both sides by I               R  =  E / I  

 

Plug in the known values                                    R  =  110 / 5  

 

                                                                           R  =  5 Ω   

.

 Oct 15, 2021
 #2
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Did somebody change this while I was asleep?  Or did I make a clumsy error?  

 

                    R  =  110 / 5       obviously does not equal 5 sheesh can't believe I did that

 

                    R  =  22 Ohms  

Guest Oct 16, 2021

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