For the triangle below, let x be the area of the circumcircle, and let y be the area of the incircle. Compute x-y
Sorry, I couldn't include the triangle but in the triangle, there is a side with length 42, length 58, and length 40. It is a right triangle with the ninetey degree angle on angle C and the side CB is 40 units long, AC is 42 units long, and BA is 58 units long. I hope this is enough infomation because I really need to know how to do this so can someone help explain how to do this. I need to learn with an explanation instead with just the answer.
Well, this took a buttload of work but I finally managed to figure it out. The answer is 697 pi :)
The center of the circumcircle of a right triangle is the midpoint of the hypotenuse.
This makes the radius of the circumcircle one-half the diameter = 58 / 2 = 29.
The area of the circumcircle is pi · 292 = 841 · pi
By a well-known theorem (a polite way to say "look it up"), the radius of the incircle of a right triangle is found
by adding the two sides together, subtracting the hypotenuse and then dividing this answer by 2.
The radius of the incircle is (40 + 42 - 58) / 2 = 12
The area of the incircle is pi · 122 = 144 · pi
Subtracting, the answer becomes 697·pi