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I need some help with a few questions:

 

1) a population of 25000 in increases by 1.2% each year

just show me how to do the recusive routine so I can answer these :

 

a) population after 4 years

b) poplation after 84 months (7 years)

 

2) investment of 700 incresses by .3 per month.

just the routine, here, too.

 

a) after 5 months

b) after 1 year (12 months)

 

plesse just show me how to set up the equation, but you can also do the others if you want

 Jan 21, 2017
 #1
avatar+37097 
+5

Example:

 

After TWO years the pop would be    25000 (1+i)^n     where i= % growth rate per year in DECIMAL and n= number of years

                                                          = 25000(1+.012)^2

 

If it asks for months you will have to change the interest rate to a MONTHLY rate   i/12   and n= months

 Jan 21, 2017
 #2
avatar+33653 
0

final population = initial population*(1 + yearly percentage/100)^number of years

a)final population = 25000*(1 + 1.2/100)^4

 

final amount = initial investment*(1 + monthly increase)^number of months

a) final amount = 700*(1 + 0.3)^5

 Jan 21, 2017
 #3
avatar+33653 
0

I've assumed that by 0.3 per month you meant exactly that.  If you meant 0.3% per month then you would have to divide the 0.3 by 100.

 Jan 21, 2017

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