+197 The circle \(2x^2=-2y^2+12x-4y+20\)is inscribed inside a square which has a pair of sides parallel to the x-axis. What is the area of the square?
+36916 2x^2 - 12x + 2y^2 + 4y = 20 arrange this into standard circle form ( (x-h)^2 + (y-k)^2 = r^2
by completing the square for x and y the radius * 2 = square side length....the area = s * s
divide by 2
x^2 - 6x + y^2 + 2y = 10 now complete the square for x and y Can you take it from here?
+36916 2x^2 - 12x + 2y^2 + 4y = 20 arrange this into standard circle form ( (x-h)^2 + (y-k)^2 = r^2
by completing the square for x and y the radius * 2 = square side length....the area = s * s
divide by 2
x^2 - 6x + y^2 + 2y = 10 now complete the square for x and y Can you take it from here?
