After Jet spent 1/9 of his money and John spent 1/3 of his money, they had the same amount of money left. How much money did each of them have in the end if both John and Jet had $1176 at first?
A==Jet, B==John
A + B ==1176.......................(1)
8/9A ==2/3B.........................(2), solve for A, B
Use substitution to get:
A==504 - what Jet started with
B==672 - what John started with.
504 - (1/9*504) ==504 - 56 ==$448 - what Jet had in the end.
672 - (1/3*672) ==672 - 224==$448 - what Jon had in the end.
+237 Let Jet had money x
then John had 1176 - x
money left after John spent 1/9 = 8/9x
money left after John spent 1/3, = 2/3 (1176 - x)
Since both had same money left
So, 8/9x = 2/3 (1176 - x)
=> 8/9x = 784 - 2/3x
=> 14/9x = 784 => x = 504
So, Initally Jet had 504 and John had 672. In the end Jet will have 504 * 8/9 = 448
and John will have 672 * 2/3 = 448
