I need to do log base 2 in long expressions such as this calculator handles. Is there a way to make it handle log base 2 instead of log base

There is a change of base formula that will allow you to change from any base to base 10:

Using common logs (that is base 10 logs):

It is: log(base) number = log(number) / log(base).

Example: If you want to find the log (in base 2) of 47:    log(base 2) 47 = log(47) / log(2)

This will work for any base:

If you want to find the log (in base 8) of 119:    log(base 8) 119 = log(119) / log(8)

This also works if you want to use natural logs:

Use the formula: log(base) number = ln(number) / ln(base).

Example: log(base 2) 47 = ln(47) / ln(2).

This is probably a question for Alan or maybe Ninja.  

That is certainly true and that is how it is usually done but maybe the calc can handle different bases - i am not sure.   

Remember your first answer? Guess what? geno3141 solved it, not Alan or Ninja! Lol!

Not quite Dragon - I am wondering if the calc can handle different bases.  That is what the question really was.

If you hover the cursor over the log key you will see ln, e^x, lg2 and 2^x pop up.  lg2 is log to the base 2.

Alternatively, you can type log(x,2) where x is the number of which you want to find log to the base 2.