+109 "For the school play, the advance tickets cost 3$, while tickets at the door cost 5$. Thirty more tickets were sold at door than in advance, and $2630 was collected. How many of each kind of ticket were sold?"
+129847 Ah......they aren't that bad....all these are similar....
Let N be the number sold at the door
Then, N -30 must be the ones sold in advance.....since 30 fewer were sold
Then
Price of an advance ticket * number sold + Price of a door ticket * number sold = total collected.....so we have
3 (N - 30) + 5N = 2630 simplify
3n -90 + 5N = 2630
8N - 90 = 2630 add 90 to both sides
8N = 2720 divide both sides by 8
N = 340 this is the number of door tickets sold
340 - 30 = 310 = the advanced tickets sold
+129847 Ah......they aren't that bad....all these are similar....
Let N be the number sold at the door
Then, N -30 must be the ones sold in advance.....since 30 fewer were sold
Then
Price of an advance ticket * number sold + Price of a door ticket * number sold = total collected.....so we have
3 (N - 30) + 5N = 2630 simplify
3n -90 + 5N = 2630
8N - 90 = 2630 add 90 to both sides
8N = 2720 divide both sides by 8
N = 340 this is the number of door tickets sold
340 - 30 = 310 = the advanced tickets sold
