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How do you find the horizontal asymptote when there is not x in the numerator?  

 

Ex.     (1/x+3)-7

 Feb 16, 2016
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Find the value of the expression as the expression goes to infinity and as the expression goes to negative infinity.

As x goes to infinity, the fraction 1/x goes to zero; so (1/x + 3) - 7 goes to (0 + 3) - 7  =  3 - 7  =  -4.

As x goes to negative infinity, the fraction 1/x again goes to zero, so the limit is again -4.

Thus, the horizontal asymptate occurs at  y =  -4.

 Feb 16, 2016

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