The cylindrical roller for a cricket pitch is 1.5 m wide and has a radius of 0.3 m.
a) Calculate the curved surface area of the roller.
b) What is the minimum number of revolutions the roller would have to make to roll the cricket pitch once
if the pitch is 20 m long and 3 m wide? (Ignore any revolutions needed to turn the roller around.)
Thought I was pretty clear....what part do you not understand..
(Please do not repost questions.....respond to original thread when you need further help....)
The pitch ( which is a playing field) that is 3 meters wide
the roller is 1.5 meters wide....so you would have to roll up one side and down the other to completely cover it : 2 passes
the circumference of the roller is pi d = pi (.6 ) m = 1.885 m per revolution
to go 20 meters you would have to go 20 m / 1.885 m/rev = 10.61 revs
but remember....you have to make TWO passes 10.61 rev per pass x 2 passes = 21.22 revolutons
Also the TOTAL area of the cylindrical roller is this:
Surface area includes the two ends 2 * pi r^2 = 2 pi (.3)2 m2
plus the lateral area pi * d * width = pi (.6)(1.5) m2
The RED part is the curved surface area your question asks for......