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The cylindrical roller for a cricket pitch is 1.5 m wide and has a radius of 0.3 m.



a)  Calculate the curved surface area of the roller.

b)  What is the minimum number of revolutions the roller would have to make to roll the cricket pitch once
if the pitch is 20 m long and 3 m wide? (Ignore any revolutions needed to turn the roller around.)

 May 19, 2020
 #1
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Thought I was pretty clear....what part do you not understand..

(Please do not repost questions.....respond to original thread when you need further help....)    cheeky

 May 19, 2020
 #2
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part b

HyperYauFarer  May 19, 2020
 #3
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The pitch ( which is a playing field)    that is 3 meters wide

     the roller is 1.5 meters wide....so you would have to roll up one side and down the other to completely cover it   :  2 passes

 

     the circumference of the roller  is pi d  = pi (.6 ) m = 1.885 m per revolution

     to go 20 meters you would have to go   20 m / 1.885 m/rev   = 10.61 revs  

             but remember....you have to make TWO passes      10.61 rev per pass x 2 passes = 21.22 revolutons

ElectricPavlov  May 19, 2020
 #4
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Also the TOTAL area of the cylindrical roller is this:

 

Surface area includes the two ends   2   *  pi r^2 = 2  pi (.3)2  m2

   plus the lateral area     pi * d * width  =   pi (.6)(1.5)  m2 

 

The RED part is the curved surface area your question asks for......

 May 19, 2020
edited by ElectricPavlov  May 19, 2020

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