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Four consecutive positive prime numbers have a sum that is divisible by three. What is the smallest possible value of this sum?

 Oct 26, 2021
 #1
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5 + 7 + 11 + 13 ==36 mod 3 ==0

 Oct 26, 2021
 #2
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Yep, when you're completely stuck on a problem, it's good to sometimes just bash it out.

Try 2, 3, 5, 7 then 3, 5, 7, 11 then 5, 7, 11, 13. 

This works well on this problem becuase it asks for the smallest value, meaning we can test from small to big sums to guarentee there isn't a smaller solution that we didn't find. 

 

=^._.^=

catmg  Oct 27, 2021

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