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I was hoping someone could help me with this question. I can't seem to figure out how to simplify it. 

Assuming that p and q are nonzero, simplify .

\(\dfrac{(pq^3)^3(4p^2q)^2}{(2pq^2)^3}\)

Guest Aug 22, 2018
 #1
avatar+200 
+1

The answer is I belive 2p^4 * q^5.

I am working on a clear step by step solution,

ColdplayMX  Aug 22, 2018
 #5
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0

Thanks!

Guest Aug 23, 2018
 #2
avatar+91381 
+1

( pq^3)^3 (4p^2q)^2

________________                using  (a^m)^n   =  a^(m * n)....so we have

     (2pq^2)^3

 

(p^3 * q^9) (4^2 * p^4 * q^2 )

_______________________

  ( 2^3 * p^3 * q^6)

 

( p^3 * q^9 * 16  * p^4  * q^2)

________________________         using  a^m * a^n  =  a^(m + n)

   (8 * p^3 * q^6)

 

16 *p^7 * q^11

_____________           using    a^m / a^n   =  a^(m - n)

     8 * p^3 * q^6 

 

2 * p^4 * q^5          just as Coldplay found   !!!!!

 

 

cool cool cool

CPhill  Aug 22, 2018
 #6
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0

Thanks!

Guest Aug 23, 2018
 #3
avatar+200 
+1

CPhill said it better than I could've. Hope it helped!

ColdplayMX  Aug 22, 2018
 #4
avatar+91381 
0

Eh....I'm pretty sjure that you could have done the same thing, Coldplay....

 

 

cool cool cool

CPhill  Aug 22, 2018

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