+0  
 
0
198
6
avatar

I was hoping someone could help me with this question. I can't seem to figure out how to simplify it. 

Assuming that p and q are nonzero, simplify .

\(\dfrac{(pq^3)^3(4p^2q)^2}{(2pq^2)^3}\)

 Aug 22, 2018
 #1
avatar+194 
+1

The answer is I belive 2p^4 * q^5.

I am working on a clear step by step solution,

 Aug 22, 2018
 #5
avatar
0

Thanks!

Guest Aug 23, 2018
 #2
avatar+94558 
+1

( pq^3)^3 (4p^2q)^2

________________                using  (a^m)^n   =  a^(m * n)....so we have

     (2pq^2)^3

 

(p^3 * q^9) (4^2 * p^4 * q^2 )

_______________________

  ( 2^3 * p^3 * q^6)

 

( p^3 * q^9 * 16  * p^4  * q^2)

________________________         using  a^m * a^n  =  a^(m + n)

   (8 * p^3 * q^6)

 

16 *p^7 * q^11

_____________           using    a^m / a^n   =  a^(m - n)

     8 * p^3 * q^6 

 

2 * p^4 * q^5          just as Coldplay found   !!!!!

 

 

cool cool cool

 Aug 22, 2018
 #6
avatar
0

Thanks!

Guest Aug 23, 2018
 #3
avatar+194 
+1

CPhill said it better than I could've. Hope it helped!

 Aug 22, 2018
 #4
avatar+94558 
0

Eh....I'm pretty sjure that you could have done the same thing, Coldplay....

 

 

cool cool cool

CPhill  Aug 22, 2018

9 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.