We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

I was hoping someone could help me with this question. I can't seem to figure out how to simplify it.

Assuming that p and q are nonzero, simplify .

\(\dfrac{(pq^3)^3(4p^2q)^2}{(2pq^2)^3}\)

Guest Aug 22, 2018

#1**+1 **

The answer is I belive 2p^4 * q^5.

I am working on a clear step by step solution,

ColdplayMX Aug 22, 2018

#2**+1 **

( pq^3)^3 (4p^2q)^2

________________ using (a^m)^n = a^(m * n)....so we have

(2pq^2)^3

(p^3 * q^9) (4^2 * p^4 * q^2 )

_______________________

( 2^3 * p^3 * q^6)

( p^3 * q^9 * 16 * p^4 * q^2)

________________________ using a^m * a^n = a^(m + n)

(8 * p^3 * q^6)

16 *p^7 * q^11

_____________ using a^m / a^n = a^(m - n)

8 * p^3 * q^6

2 * p^4 * q^5 just as Coldplay found !!!!!

CPhill Aug 22, 2018