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Identify the conic section.

 

4x^2 + 7y^2 + 32x - 56y + 148 = 0 

 

Correct me if I'm wrong, but I think it's  hyperbola with center (4, 4) and foci at (-4, 5.73), (-4, 2.27)?

 

thanks!

 Mar 27, 2015

Best Answer 

 #4
avatar+118703 
+10

NOTE that your earlier hyperbola had a minus sign between the squared terms

and

The ellipse as a positive sign.   If the numbers on  the botton were the same then it would be a circle. 

A circle is a special case of an elipse because it has a double focii instead of 2 separate focii. 

Effectively a cirlce has one centre and other ellipses have 2 centres.

 Mar 27, 2015
 #1
avatar+118703 
+10
 Mar 27, 2015
 #5
avatar+776 
0

OMG!!! you use desmos to!!!!!!!

User101  Apr 16, 2016
 #2
avatar+118703 
+10

4x2+7y2+32x56y+148=04x2+32x+7y256y=1484(x2+8x)+7(y28y)=1484(x2+8x+16)+7(y28y+16)=148+416+7164(x+4)2+7(y4)2=284(x+4)228+7(y4)228=1(x+4)27+(y4)24=1(x+4)2(7)2+(y4)222=1

 

This is an ellipse centre (-4,+4)

 

The ends of the major axis are   (47,4)and(4+7,4)

 

Then ends of the minor axis are  (-4,4-2) (-4,4+2)  that is    (4,2)and(4,6)

 

references

http://www.mathsisfun.com/geometry/ellipse.html

http://en.wikipedia.org/wiki/Ellipse

 Mar 27, 2015
 #3
avatar+118703 
+3

Oh and Welcome to the forum Tyler :)

 Mar 27, 2015
 #4
avatar+118703 
+10
Best Answer

NOTE that your earlier hyperbola had a minus sign between the squared terms

and

The ellipse as a positive sign.   If the numbers on  the botton were the same then it would be a circle. 

A circle is a special case of an elipse because it has a double focii instead of 2 separate focii. 

Effectively a cirlce has one centre and other ellipses have 2 centres.

Melody Mar 27, 2015

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