Identify the conic section.
4x^2 + 7y^2 + 32x - 56y + 148 = 0
Correct me if I'm wrong, but I think it's hyperbola with center (4, 4) and foci at (-4, 5.73), (-4, 2.27)?
thanks!
NOTE that your earlier hyperbola had a minus sign between the squared terms
and
The ellipse as a positive sign. If the numbers on the botton were the same then it would be a circle.
A circle is a special case of an elipse because it has a double focii instead of 2 separate focii.
Effectively a cirlce has one centre and other ellipses have 2 centres.
4x2+7y2+32x−56y+148=04x2+32x+7y2−56y=−1484(x2+8x)+7(y2−8y)=−1484(x2+8x+16)+7(y2−8y+16)=−148+4∗16+7∗164(x+4)2+7(y−4)2=284(x+4)228+7(y−4)228=1(x+4)27+(y−4)24=1(x+4)2(√7)2+(y−4)222=1
This is an ellipse centre (-4,+4)
The ends of the major axis are (−4−√7,4)and(−4+√7,4)
Then ends of the minor axis are (-4,4-2) (-4,4+2) that is (−4,2)and(−4,6)
references
NOTE that your earlier hyperbola had a minus sign between the squared terms
and
The ellipse as a positive sign. If the numbers on the botton were the same then it would be a circle.
A circle is a special case of an elipse because it has a double focii instead of 2 separate focii.
Effectively a cirlce has one centre and other ellipses have 2 centres.