idk what to do as the title by this point

First one:

6a^2 + 5a + 4 = 3,

6a^2 +5a +1 = 0      Now use Quadratic Formula to find the two values of a  ....use the smaller one to calculate   2a + 1

25^x-9^y=18

5^x-3^y=3          Multiply this equation by -4      add it to the first equation ...and see what you get !

2(3-i)+i(2+i).    expand

6 - 2i  + 2i  + i^2        =    ????      (remember  i^2 = - 1)

1) If 6a^2 + 5a + 4 = 3, then what is the smallest possible value of 2a + 1?

2) If we are given x such that 25^x-9^y=18 and 5^x-3^y=3, compute 5^x+3^y.