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avatar+95 

1)

 

If 6a^2 + 5a + 4 = 3, then what is the smallest possible value of 2a + 1?

 

2)

 

If we are given x such that 25^x-9^y=18 and 5^x-3^y=3, compute 5^x+3^y.

 

3)

 

Simplify 2(3-i)+i(2+i).

 Jan 21, 2020
 #1
avatar+23562 
+3

First one:

 

6a^2 + 5a + 4 = 3,

6a^2 +5a +1 = 0      Now use Quadratic Formula to find the two values of a  ....use the smaller one to calculate   2a + 1

 

25^x-9^y=18

5^x-3^y=3          Multiply this equation by -4      add it to the first equation ...and see what you get !

 

2(3-i)+i(2+i).    expand

6 - 2i  + 2i  + i^2        =    ????      (remember  i^2 = - 1)

 Jan 21, 2020
 #2
avatar+12186 
+2

1) If 6a^2 + 5a + 4 = 3, then what is the smallest possible value of 2a + 1?

2) If we are given x such that 25^x-9^y=18 and 5^x-3^y=3, compute 5^x+3^y.

laugh

 Jan 21, 2020
edited by Omi67  Jan 21, 2020

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