If 6a^2 + 5a + 4 = 3, then what is the smallest possible value of 2a + 1?
If we are given x such that 25^x-9^y=18 and 5^x-3^y=3, compute 5^x+3^y.
6a^2 + 5a + 4 = 3,
6a^2 +5a +1 = 0 Now use Quadratic Formula to find the two values of a ....use the smaller one to calculate 2a + 1
5^x-3^y=3 Multiply this equation by -4 add it to the first equation ...and see what you get !
6 - 2i + 2i + i^2 = ???? (remember i^2 = - 1)