If 1/21 equals the repeating decimal 0.0476190476190..., what is the 51^{st} digit after the decimal point of the repeating decimal?

I believe that it is 7 because every 6 characters the cycle repeats. So 8 of these cycles means that the 49th character would be a 0 .. 50 would be a 4 and the 51st digit would be a 7.