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If 4 numbers from 1 to 1000 are chosen at random, one at a time, find the probability that they will be all multiples of 3.

 Nov 2, 2020
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If I understand your question:

 

There are: 1000 / 3 =333 numbers that are multiples of 3

 

First number =333 / 1000 x second number =332 /999 x third number =331 /998 x fourth number =330/997=[333 / 1000  x  332/999  x  331/998  x  330/997] =12,076,031,880/ 994,010,994,000==302203/24875150==1.215%

 Nov 2, 2020

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